Let’s apply the inventory management model discussed in 4.1 to a specific example, which is as follows: three types of semi-finished products are produced on the same equipment.
The object of modeling is a warehouse of finished products, a system for managing the movement of stocks, taking into account restrictions on warehouse space and working capital.
Problem situation – determination of the optimal values of the batch of delivery of semi-finished products, their maximum stock level, production time, deficit-free and scarce operation of the inventory management system for each type of semi-finished products under given conditions.
Observed parameters:
the cost of adjustments of Ki equipment [d. units], which does not depend on the order of release of semi-finished products, which are then sent to nearby warehouses with a total area of F = 300 m?; the cost of maintaining a unit of stock of semi-finished products Si
[den. units/ (unit p/fabr.: ed. time)]; λi rate of arrival [ unit p/factory: (unit time) ]; velocity of expenditure Vi [ unit n/factory: (unit time) ]; standards for warehouses fi [ m/(unit p/factory) ]; standards for working capital αi [ d. units / units p / fabr.]; losses from deficiency di [ d.u./(unit p/fabr.:ed. time) ]; the amount of working capital should not exceed the value; A0 = 20000 [ di. units].
Unobservable parameters:
batches of delivery of semi-finished products Qi* ; maximum level of stocks of semi-finished products Yi* ; production time of semi-finished products ?pri*; time of stock formation ?i1*; time to eliminate the deficit ?i4*; the time of expenditure of the stock ?i2*; Hi* deficit-free operation time; operating time in the presence of a deficiency of Ni* for each type of semi-finished product.
Adequacy – compliance with the estimated and actual parameters of the inventory management system.
Mathematical apparatus – differential calculus, partial derivatives, algebraic equations.
The result of the simulation is the organization of the optimal inventory management system; optimal values of the batch of delivery of semi-finished products qi*, the maximum level of stocks of semi-finished products Yi*; production time of semi-finished products ?pri*; time of stock formation ?i1*; time to eliminate the deficit ?i4*; the time of expenditure of the stock ?i2*; Hi* deficit-free operation time; operating time in the presence of a deficit of Ni* for each type of semi-finished product (Table. 4.1.).
Table 4.1.
Initial data on semi-finished products.
I | Vi | λi | Ki | Si | di | fi | αi |
1 | 49 | 245 | 52 | 6 | 18 | 1,5 | 50 |
2 | 178 | 685 | 78 | 8 | 32 | 1,4 | 50 |
3 | 266 | 1520 | 43 | 10 | 20 | 2 | 100 |
To solve this problem, a model should be used taking into account the unmet requirements of multi-product production.
In this regard, auxiliary data are preliminarily calculated:
Vi/λi , Аi=1 – Vi/λi , Mi= S i / d i , Bi=1 – S i / d i , R i = S i· Vi · Ai/Bi
Then the optimal time to resume deliveries:
?c*=?2· ?i Ki / [?i(S i· Vi · Ai / Bi)]
Substituting the numeric values of the original data, we get the values of the auxiliary data (Table. 4.2.).
Table 4.2.
Auxiliary data values
i | Ai | Mi | Bi | R i |
1 | 0,8 | 0,33 | 0,67 | 351,05 |
2 | 0,74 | 0,25 | 0,75 | 1405,01 |
3 | 0,825 | 0,5 | 0,5 | 4389 |
The required optimal parameters of inventory management are calculated using the following formulas:
qi*= Vi ·? c*
?pri*= qi*/λi
?i1*= ?pri*/ Bi
?i4*= ?pri*- ?i1*
?i2*= ?c*· Ai/ Bi (4-31)
Hi* = ?i1*+ ?i2*
Ni* = Hi*+ Mi
Yi* = qi· (1+ Vi)/λi
Substituting numerical data, we get (Table 4.3.):
Table 4.3.
Optimal parameters of the inventory management system
I | qi* | ?pri* | ?i1* | ?i4* | ?i2* | Hi* | Ni* | Yi* |
1 | 11,61 | 0,05 | 0,07 | 0,02 | 0,28 | 0,35 | 0,68 | 2,37 |
2 | 42,19 | 0,06 | 0,08 | 0,02 | 0,23 | 0,31 | 0,56 | 11,02 |
3 | 63,04 | 0,04 | 0,08 | 0,04 | 0,39 | 0,47 | 0,97 | 11,07 |
Let’s check the restrictions:
by warehouses
? F =F/?i fi· Vi, ? F = 0.35 times
on working capital
? A= A0/?i αi · Vi, ? A = 0.53 times
Since ?c* < ? F < ? A, then recalculation of the obtained optimal parameters (Table. 4.3.) is not required.